Skip Headers
Oracle® Database SQL Language Reference
12c Release 1 (12.1)

E17209-15
Go to Documentation Home
Home
Go to Book List
Book List
Go to Table of Contents
Contents
Go to Index
Index
Go to Master Index
Master Index
Go to Feedback page
Contact Us

Go to previous page
Previous
Go to next page
Next
PDF · Mobi · ePub

RANK

Aggregate Syntax

rank_aggregate::=

Description of rank_aggregate.gif follows
Description of the illustration rank_aggregate.gif

Analytic Syntax

rank_analytic::=

Description of rank_analytic.gif follows
Description of the illustration rank_analytic.gif

See Also:

"Analytic Functions" for information on syntax, semantics, and restrictions

Purpose

RANK calculates the rank of a value in a group of values. The return type is NUMBER.

See Also:

Table 2-10, "Implicit Type Conversion Matrix" for more information on implicit conversion and "Numeric Precedence" for information on numeric precedence

Rows with equal values for the ranking criteria receive the same rank. Oracle Database then adds the number of tied rows to the tied rank to calculate the next rank. Therefore, the ranks may not be consecutive numbers. This function is useful for top-N and bottom-N reporting.

Aggregate Example

The following example calculates the rank of a hypothetical employee in the sample table hr.employees with a salary of $15,500 and a commission of 5%:

SELECT RANK(15500, .05) WITHIN GROUP
   (ORDER BY salary, commission_pct) "Rank"
   FROM employees;

      Rank
----------
       105

Similarly, the following query returns the rank for a $15,500 salary among the employee salaries:

SELECT RANK(15500) WITHIN GROUP 
   (ORDER BY salary DESC) "Rank of 15500" 
   FROM employees;

Rank of 15500
--------------
             4

Analytic Example

The following statement ranks the employees in the sample hr schema in department 60 based on their salaries. Identical salary values receive the same rank and cause nonconsecutive ranks. Compare this example with the analytic example for DENSE_RANK.

SELECT department_id, last_name, salary,
       RANK() OVER (PARTITION BY department_id ORDER BY salary) RANK
  FROM employees WHERE department_id = 60
  ORDER BY RANK, last_name;

DEPARTMENT_ID LAST_NAME                     SALARY       RANK
------------- ------------------------- ---------- ----------
           60 Lorentz                         4200          1
           60 Austin                          4800          2
           60 Pataballa                       4800          2
           60 Ernst                           6000          4
           60 Hunold                          9000          5