NAME

dtzrzf - reduce the M-by-N ( M<=N ) real upper trapezoidal matrix A to upper triangular form by means of orthogonal transformations


SYNOPSIS

  SUBROUTINE DTZRZF( M, N, A, LDA, TAU, WORK, LWORK, INFO)
  INTEGER M, N, LDA, LWORK, INFO
  DOUBLE PRECISION A(LDA,*), TAU(*), WORK(*)
  SUBROUTINE DTZRZF_64( M, N, A, LDA, TAU, WORK, LWORK, INFO)
  INTEGER*8 M, N, LDA, LWORK, INFO
  DOUBLE PRECISION A(LDA,*), TAU(*), WORK(*)

F95 INTERFACE

  SUBROUTINE TZRZF( [M], [N], A, [LDA], TAU, [WORK], [LWORK], [INFO])
  INTEGER :: M, N, LDA, LWORK, INFO
  REAL(8), DIMENSION(:) :: TAU, WORK
  REAL(8), DIMENSION(:,:) :: A
  SUBROUTINE TZRZF_64( [M], [N], A, [LDA], TAU, [WORK], [LWORK], [INFO])
  INTEGER(8) :: M, N, LDA, LWORK, INFO
  REAL(8), DIMENSION(:) :: TAU, WORK
  REAL(8), DIMENSION(:,:) :: A

C INTERFACE

#include <sunperf.h>

void dtzrzf(int m, int n, double *a, int lda, double *tau, int *info);

void dtzrzf_64(long m, long n, double *a, long lda, double *tau, long *info);


PURPOSE

dtzrzf reduces the M-by-N ( M<=N ) real upper trapezoidal matrix A to upper triangular form by means of orthogonal transformations.

The upper trapezoidal matrix A is factored as

   A = ( R  0 ) * Z,

where Z is an N-by-N orthogonal matrix and R is an M-by-M upper triangular matrix.


ARGUMENTS


FURTHER DETAILS

Based on contributions by

  A. Petitet, Computer Science Dept., Univ. of Tenn., Knoxville, USA

The factorization is obtained by Householder's method. The kth transformation matrix, Z( k ), which is used to introduce zeros into the ( m - k + 1 )th row of A, is given in the form

   Z( k )  = ( I     0   ),
            ( 0  T( k ) )

where

   T( k )  = I - tau*u( k )*u( k )',   u( k )  = (   1    ),
                                               (   0    )
                                               ( z( k ) )

tau is a scalar and z( k ) is an ( n - m ) element vector. tau and z( k ) are chosen to annihilate the elements of the kth row of X.

The scalar tau is returned in the kth element of TAU and the vector u( k ) in the kth row of A, such that the elements of z( k ) are in a( k, m + 1 ), ..., a( k, n ). The elements of R are returned in the upper triangular part of A.

Z is given by

   Z  =  Z( 1 ) * Z( 2 ) * ... * Z( m ).