dtzrzf - reduce the M-by-N ( M<=N ) real upper trapezoidal matrix A to upper triangular form by means of orthogonal transformations
SUBROUTINE DTZRZF( M, N, A, LDA, TAU, WORK, LWORK, INFO) INTEGER M, N, LDA, LWORK, INFO DOUBLE PRECISION A(LDA,*), TAU(*), WORK(*)
SUBROUTINE DTZRZF_64( M, N, A, LDA, TAU, WORK, LWORK, INFO) INTEGER*8 M, N, LDA, LWORK, INFO DOUBLE PRECISION A(LDA,*), TAU(*), WORK(*)
SUBROUTINE TZRZF( [M], [N], A, [LDA], TAU, [WORK], [LWORK], [INFO]) INTEGER :: M, N, LDA, LWORK, INFO REAL(8), DIMENSION(:) :: TAU, WORK REAL(8), DIMENSION(:,:) :: A
SUBROUTINE TZRZF_64( [M], [N], A, [LDA], TAU, [WORK], [LWORK], [INFO]) INTEGER(8) :: M, N, LDA, LWORK, INFO REAL(8), DIMENSION(:) :: TAU, WORK REAL(8), DIMENSION(:,:) :: A
#include <sunperf.h>
void dtzrzf(int m, int n, double *a, int lda, double *tau, int *info);
void dtzrzf_64(long m, long n, double *a, long lda, double *tau, long *info);
dtzrzf reduces the M-by-N ( M<=N ) real upper trapezoidal matrix A to upper triangular form by means of orthogonal transformations.
The upper trapezoidal matrix A is factored as
A = ( R 0 ) * Z,
where Z is an N-by-N orthogonal matrix and R is an M-by-M upper triangular matrix.
WORK(1)
returns the optimal LWORK.
If LWORK = -1, then a workspace query is assumed; the routine only calculates the optimal size of the WORK array, returns this value as the first entry of the WORK array, and no error message related to LWORK is issued by XERBLA.
= 0: successful exit
< 0: if INFO = -i, the i-th argument had an illegal value
Based on contributions by
A. Petitet, Computer Science Dept., Univ. of Tenn., Knoxville, USA
The factorization is obtained by Householder's method. The kth transformation matrix, Z( k ), which is used to introduce zeros into the ( m - k + 1 )th row of A, is given in the form
Z( k ) = ( I 0 ),
( 0 T( k ) )
where
T( k ) = I - tau*u( k )*u( k )', u( k ) = ( 1 ), ( 0 ) ( z( k ) )
tau is a scalar and z( k ) is an ( n - m ) element vector. tau and z( k ) are chosen to annihilate the elements of the kth row of X.
The scalar tau is returned in the kth element of TAU and the vector u( k ) in the kth row of A, such that the elements of z( k ) are in a( k, m + 1 ), ..., a( k, n ). The elements of R are returned in the upper triangular part of A.
Z is given by
Z = Z( 1 ) * Z( 2 ) * ... * Z( m ).