NAME

ztzrzf - reduce the M-by-N ( M<=N ) complex upper trapezoidal matrix A to upper triangular form by means of unitary transformations


SYNOPSIS

  SUBROUTINE ZTZRZF( M, N, A, LDA, TAU, WORK, LWORK, INFO)
  DOUBLE COMPLEX A(LDA,*), TAU(*), WORK(*)
  INTEGER M, N, LDA, LWORK, INFO
  SUBROUTINE ZTZRZF_64( M, N, A, LDA, TAU, WORK, LWORK, INFO)
  DOUBLE COMPLEX A(LDA,*), TAU(*), WORK(*)
  INTEGER*8 M, N, LDA, LWORK, INFO

F95 INTERFACE

  SUBROUTINE TZRZF( [M], [N], A, [LDA], TAU, [WORK], [LWORK], [INFO])
  COMPLEX(8), DIMENSION(:) :: TAU, WORK
  COMPLEX(8), DIMENSION(:,:) :: A
  INTEGER :: M, N, LDA, LWORK, INFO
  SUBROUTINE TZRZF_64( [M], [N], A, [LDA], TAU, [WORK], [LWORK], [INFO])
  COMPLEX(8), DIMENSION(:) :: TAU, WORK
  COMPLEX(8), DIMENSION(:,:) :: A
  INTEGER(8) :: M, N, LDA, LWORK, INFO

C INTERFACE

#include <sunperf.h>

void ztzrzf(int m, int n, doublecomplex *a, int lda, doublecomplex *tau, int *info);

void ztzrzf_64(long m, long n, doublecomplex *a, long lda, doublecomplex *tau, long *info);


PURPOSE

ztzrzf reduces the M-by-N ( M<=N ) complex upper trapezoidal matrix A to upper triangular form by means of unitary transformations.

The upper trapezoidal matrix A is factored as

   A = ( R  0 ) * Z,

where Z is an N-by-N unitary matrix and R is an M-by-M upper triangular matrix.


ARGUMENTS


FURTHER DETAILS

Based on contributions by

  A. Petitet, Computer Science Dept., Univ. of Tenn., Knoxville, USA

The factorization is obtained by Householder's method. The kth transformation matrix, Z( k ), which is used to introduce zeros into the ( m - k + 1 )th row of A, is given in the form

   Z( k )  = ( I     0   ),
            ( 0  T( k ) )

where

   T( k )  = I - tau*u( k )*u( k )',   u( k )  = (   1    ),
                                               (   0    )
                                               ( z( k ) )

tau is a scalar and z( k ) is an ( n - m ) element vector. tau and z( k ) are chosen to annihilate the elements of the kth row of X.

The scalar tau is returned in the kth element of TAU and the vector u( k ) in the kth row of A, such that the elements of z( k ) are in a( k, m + 1 ), ..., a( k, n ). The elements of R are returned in the upper triangular part of A.

Z is given by

   Z  =  Z( 1 ) * Z( 2 ) * ... * Z( m ).