Drill Bit Replacement Problem Statement

When drilling wells in certain types of terrain, the performance of a drill bit erodes with time because of wear. After T hours, the drilling rate can be expressed as:

Drilling rate formula.

For example, after 5 hours of consecutive use (starting with a new drill bit), the drill is able to penetrate the terrain at a rate of:

Drilling rate formula example after 5 hours of consecutive use, the drill is able to penetrate the terrain at a rate of 22.21 meters per hour.

While after 50 hours, the penetration rate is only:

Drilling rate formula example after 50 hours of consecutive use, the drill is able to penetrate the terrain at a rate of 6.71 meters per hour.

Eventually, the bit must be replaced as the costs exceed the value of the well being drilled. The problem is to determine the optimum replacement policy; that is, the drilling cycle, T hours, between replacements.

T hours after replacing the bit, the total drilled depth in meters, M, is given by the integral of Equation 4.2 from 0 to T, or:

Drilling depth formula.

where 300 is a drilling depth coefficient.

The revenue value per meter drilled is calculated to be $60. Drilling expenses are fixed at $425 per hour, and it generally requires R = 7.5 hours to install a new drill bit, at a cost of $8,000 + $400R.

If all drilling parameters were certain, calculating the optimal replacement policy would be straightforward. However, several of the drilling parameters are uncertain, and knowledge about their values must be assumed:

With these assumptions, the profit/drilling cycle if the bit is replaced after T hours equals the revenue obtained from drilling minus drilling expenses and replacement costs:

profit/drilling cycle = $60M - $425T - ($8,000 + $400R)

Assuming D ten-hour days per month, the average number of cycles per month is 10D/(T + R). Therefore, the average profit per month is:

Average drilling profit formula.

The objective is to find the value of T that maximizes the average profit per month.