Use this function to find out whether or not the specified year is a leap year.
|
Parameter |
Description |
|
Year |
Enter the year. You can enter either a two- or four-digit number. If you enter a two-digit number, the current century is added to create the year value. The default is the current year. |
The system returns one (1) if the year is a leap year and zero (0) if it is not.
This function is most often used with the Year function. The Year function extracts the year number from a given date.
Here are some examples:
(Assume the current date is 07/01/08.)
|
Function |
Result |
Explanation |
|
LeapYear ( ) |
1 |
The parameter defaults to the current year (2008). Since 2008 is a leap year, one (1), which represents true, is the result. |
|
LeapYear (07) |
0 |
The year 2007 was not a leap year. Therefore, the result is zero (0), representing false. |
|
LeapYear (Year ("2009/09/09", "34") ) |
0 |
First the Year function extracts the year number (2009) from the date, which is given in the date format "34". Then LeapYear determines that 2009 is not a leap year and returns zero (0.) |
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