This function returns paths into p_values that match a given pattern.
Syntax
APEX_JSON.FIND_PATHS_LIKE (
    p_return_path      IN VARCHAR2,
    p_subpath          IN VARCHAR2 DEFAULT NULL,
    p_value            IN VARCHAR2 DEFAULT NULL,
    p_values           IN t_values DEFAULT g_values )
RETURN apex_t_varchar2;
Parameters
Table 15-3 FIND_PATHS_LIKE Function Parameters
| Parameter | Description | 
|---|---|
| 
 | Search pattern for the return path.. | 
| 
 | Search pattern under  | 
| 
 | Search pattern for value (optional). | 
| 
 | Parsed JSON members. The default is  | 
Returns/Raised Errors
Table 15-4 FIND_PATHS_LIKE Function Returns and Raised Errors
| Return | Description | 
|---|---|
| 
 | Table of paths that match the pattern. | 
| 
 | Raises this error if  | 
Example
This example parses a JSON string, finds paths that match a pattern, and prints the values under the paths.
DECLARE
    j            apex_json.t_values;
    l_paths apex_t_varchar2;
BEGIN
    apex_json.parse(j, '{ "items": [ { "name": "Amulet of Yendor", "magical": true }, '||
                                     { "name": "Slippers",  "magical": "rather not" } ]}');
    l_paths := apex_json.find_paths_like (
        p_values         => j,
        p_return_path => 'items[%]',
        p_subpath       => '.magical',
        p_value           => 'true' );
    dbms_output.put_line('Magical items:');
    for i in 1 .. l_paths.count loop
        dbms_output.put_line(apex_json.get_varchar2(p_values => j, p_path => l_paths(i)||'.name')); 
    end loop;
END;