FindNode method: XmlNode class

Syntax

FindNode(Path)

Description

Use the FindNode method to return a reference to an XmlNode.

The path is specified as the list of tag names, to the node that you want to find, each separated by a slash (/).

Parameters

Parameter	Description
Path	Specify the tag names up to and including the name of the node that you want returned, starting with a slash and each separated by a slash (/). This is known as the XPath query language. See XML Path Language (XPath) Version 1.0.

Returns

An XmlNode matching the path if successful. If not successful, the IsNull property on the XmlNode is set to True.

Example

Suppose your XmlDoc has the following structure:

<?xml version="1.0"?> 
<myroot> 
   <postreqresponse> 
      <candidate> 
         <user> 
            <location scenery="great" density="low" blank="eh?"/>
         </user> 
      </candidate> 
   </postreqresponse> 
</myroot>

You want to return a reference to the location attribute. Use the following Path to do it:

&XmlNode = &MyDoc.FindNode("/myroot/postreqresponse/candidate/user/location");