GetNumber method: JsonObject class
Syntax
GetNumber(Name)
Description
Use this method to return the number value of the property mentioned by the input parameter.
Parameters
| Parameter | Description |
|---|---|
|
Name |
Specifies the name of the number object as a string. |
Returns
Number.
Example
Local JsonObject &jObj = CreateJsonObject();
&jObj.AddProperty("Salary", "TYPE_NUMBER");
Local Number &jn = &jObj.GetNumber("Salary");