DateTime6 function
Syntax
DateTime6(year, month, day, hour, minute, second)
Description
The DateTime6 function returns a DateTime value based on integer values for the year, month, day, hour, minute, and second. If the result of this function is not an actual date, there is a runtime error.
WARNING:
Make sure that you pass a four-digit year in the year parameter of this function. Two-digit values will be interpreted literally: 93, for example, represents the year 93 AD.
Parameters
| Parameter | Description |
|---|---|
|
year |
A four-digit number representing the year. |
|
month |
A number between 1 and 12 representing the month. |
|
day |
A number representing the day of the month. |
|
hour |
A number from 0 to 23 representing the hour of the day. |
|
minute |
A number from 0 to 59 representing the minute of the hour. |
|
second |
A number from 0 to 59.999999 representing seconds. |
Returns
Returns a DateTime value based on the integers provided.
Example
The following example sets &DTTM to a DateTime value equal to 10:09:20 on March 15, 1997:
&DTTM = DateTime6(1997, 3, 15, 10, 9, 20);