GROUPING
The GROUPING function enables you to determine whether a NULL is a stored NULL or an indication of a subtotal or grand total. Using a single column as its argument, GROUPING returns a 1 when it encounters a null value created by a ROLLUP or CUBE operation, indicating a subtotal or grand total. Any other type of value, including a stored NULL, returns a 0.
Note:
See "GROUP BY Clause" for details on ROLLUP and CUBE clauses.
Syntax
The GROUPING function is applicable only in a SELECT statement that contains a GROUP BY clause. It can be used in the select list and HAVING clause of the SELECT query that includes the GROUP BY clause. The expression indicated in the GROUPING function syntax must match one of the expressions contained in the GROUP BY clause.
The following syntax uses GROUPING to identify the results from the expression listed as an aggregate or not:
SELECT ... [GROUPING(Expression) ... ] ... GROUP BY ... { RollupCubeClause | GroupingSetsClause } ...
The following syntax uses GROUPING within a HAVING clause to identify the results from the expression listed as an aggregate or not:
SELECT ...
GROUP BY ... { RollupCubeClause | GroupingSetsClause } ...
HAVING GROUPING(Expression) = 1Parameters
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Valid expression syntax. See Expressions. |
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The |
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Examples
The following example shows how the grouping function returns a '1' when it encounters the grand total for the department.
Command> columnlabels on;
Command> SELECT department_id AS DEPT,
GROUPING(department_id) AS DEPT_GRP, SUM(salary) AS SALARY
FROM emp_details_view
GROUP BY ROLLUP(department_id)
ORDER BY department_id;
DEPT, DEPT_GRP, SALARY
< 10, 0, 4400 >
< 20, 0, 19000 >
< 30, 0, 24900 >
< 40, 0, 6500 >
< 50, 0, 156400 >
< 60, 0, 28800 >
< 70, 0, 10000 >
< 80, 0, 304500 >
< 90, 0, 58000 >
< 100, 0, 51600 >
< 110, 0, 20300 >
< <NULL>, 1, 684400 >
12 rows found.
The following example shows that you can use the GROUPING function for each column to determine which null values are for the totals.
Command> SELECT department_id AS DEPT, job_id AS JOB,
GROUPING(department_id) AS DEPT_GRP, GROUPING(job_id) AS JOB_GRP,
GROUPING_ID(department_id, job_id) AS GRP_ID, SUM(salary) AS SALARY
FROM emp_details_view
GROUP BY CUBE(department_id, job_id)
ORDER BY department_id, job_id, grp_id ASC;
DEPT, JOB, DEPT_GRP, JOB_GRP, GRP_ID, SALARY
< 10, AD_ASST, 0, 0, 0, 4400 >
< 10, <NULL>, 0, 1, 1, 4400 >
< 20, MK_MAN, 0, 0, 0, 13000 >
< 20, MK_REP, 0, 0, 0, 6000 >
< 20, <NULL>, 0, 1, 1, 19000 >
< 30, PU_CLERK, 0, 0, 0, 13900 >
< 30, PU_MAN, 0, 0, 0, 11000 >
< 30, <NULL>, 0, 1, 1, 24900 >
...
< 110, AC_ACCOUNT, 0, 0, 0, 8300 >
< 110, AC_MGR, 0, 0, 0, 12000 >
< 110, <NULL>, 0, 1, 1, 20300 >
< <NULL>, AC_ACCOUNT, 1, 0, 2, 8300 >
< <NULL>, AC_MGR, 1, 0, 2, 12000 >
< <NULL>, AD_ASST, 1, 0, 2, 4400 >
< <NULL>, AD_PRES, 1, 0, 2, 24000 >
< <NULL>, AD_VP, 1, 0, 2, 34000 >
< <NULL>, FI_ACCOUNT, 1, 0, 2, 39600 >
< <NULL>, FI_MGR, 1, 0, 2, 12000 >
< <NULL>, HR_REP, 1, 0, 2, 6500 >
< <NULL>, IT_PROG, 1, 0, 2, 28800 >
< <NULL>, MK_MAN, 1, 0, 2, 13000 >
< <NULL>, MK_REP, 1, 0, 2, 6000 >
< <NULL>, PR_REP, 1, 0, 2, 10000 >
< <NULL>, PU_CLERK, 1, 0, 2, 13900 >
< <NULL>, PU_MAN, 1, 0, 2, 11000 >
< <NULL>, SA_MAN, 1, 0, 2, 61000 >
< <NULL>, SA_REP, 1, 0, 2, 243500 >
< <NULL>, SH_CLERK, 1, 0, 2, 64300 >
< <NULL>, ST_CLERK, 1, 0, 2, 55700 >
< <NULL>, ST_MAN, 1, 0, 2, 36400 >
< <NULL>, <NULL>, 1, 1, 3, 684400 >
50 rows found.