Use this function to get the path component of a file name.
| 
                         Parameter  | 
                    
                         Description  | 
                
| 
                         FullFileName  | 
                    
                         Enter a string that contains a fully qualified file name, such as: "d:\mypath\myfile.ext"  | 
                
The system returns a string that contains the path component of that file name.
MYPATH = FilePath("d:\mypath\myfile.ext")
In this example, MYPATH would contain:
"\mypath\"
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