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Mid Statement
Mid replaces part (or all) of one string with another, starting at a specified location.
Syntax
Mid (stringVar, start[, length]) = string
Returns
The value of stringVar with string embedded at the specified location.
Usage
If the length argument is omitted, or if there are fewer characters in string than specified in length, then Mid replaces the characters from the start to the end of the string. If start is larger than the number of characters in the indicated stringVar, then Mid appends string to stringVar.
If length is greater than the length of string, then length is set to the length of string. If start is greater than the number of characters in stringVar, an illegal function call error occurs at runtime. If length plus start is greater than the length of stringVar, then only the characters up to the end of stringVar are replaced.
Mid never changes the number of characters in stringVar.
The index of the first character in a string is 1.
Example
This example uses the Mid statement to replace the last name in a user-entered string with asterisks (*).
Sub Button_Click
Dim username as String
Dim position as Integer
Dim count as Integer
Dim uname as String
Dim replacement as String
username = "Chris Smith"
uname = username
replacement = "*"
Do
position = InStr(username," ")
If position = 0 then
Exit Do
End If
username = Mid(username,position + 1)
count = count + position
Loop
For x = 1 to Len(username)
count = count + 1
Mid(uname,count) = replacement
Next x
End SubSee Also
LCase Function
Left Function
Len Function
LTrim Function
Mid Statement
Right Function
RTrim Function
Trim Function
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Siebel VB Language Reference Published: 18 June 2003 |