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Mid replaces part (or all) of one string with another, starting at a specified location.
Mid (stringVar, start[, length]) = string
The string to be changed
An integer representing the position in stringVar at which to begin replacing characters
An integer representing the number of characters to replace
The string to place into stringVar
The value of stringVar with string embedded at the specified location.
If the length argument is omitted, or if there are fewer characters in string than specified in length, then Mid replaces the characters from the start to the end of the string. If start is larger than the number of characters in the indicated stringVar, then Mid appends string to stringVar.
If length is greater than the length of string, then length is set to the length of string. If start is greater than the number of characters in stringVar, an illegal function call error occurs at runtime. If length plus start is greater than the length of stringVar, then only the characters up to the end of stringVar are replaced.
Mid never changes the number of characters in stringVar.
The index of the first character in a string is 1.
This example uses the Mid statement to replace the last name in a user-entered string with asterisks (*).
Dim username as String
Dim position as Integer
Dim count as Integer
Dim uname as String
Dim replacement as String
username = "Chris Smith"
uname = username
replacement = "*"
position = InStr(username," ")
If position = 0 then
username = Mid(username,position + 1)
count = count + position
For x = 1 to Len(username)
count = count + 1
Mid(uname,count) = replacement